((3x+1)/(x^2-5))/((6x-4)/(x^2-5))=0

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Solution for ((3x+1)/(x^2-5))/((6x-4)/(x^2-5))=0 equation: 


D( x )

(6*x-4)/(x^2-5) = 0

x^2-5 = 0

(6*x-4)/(x^2-5) = 0

(6*x-4)/(x^2-5) = 0

6*x-4 = 0 // + 4

6*x = 4 // : 6

x = 4/6

x = 2/3

x^2-5 = 0

x^2-5 = 0

1*x^2 = 5 // : 1

x^2 = 5

x^2 = 5 // ^ 1/2

abs(x) = 5^(1/2)

x = 5^(1/2) or x = -5^(1/2)

x in (-oo:-5^(1/2)) U (-5^(1/2):2/3) U (2/3:5^(1/2)) U (5^(1/2):+oo)

((3*x+1)/(x^2-5))/((6*x-4)/(x^2-5)) = 0

((3*x+1)*(x^2-5))/((x^2-5)*(6*x-4)) = 0

(3*x+1)/(6*x-4) = 0

3*x+1 = 0 // - 1

3*x = -1 // : 3

x = -1/3

x = -1/3

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